Film loop: "Conservation of energy: Pole vault", 3:55 min.

Film Loop: Conservation of Energy: The Pole Vault Length(min.):3:55 Color: No Sound: No This quantitative film was designed for students to study conservation of energy. A pole vaulter (mass 68 kg., height 6 ft.) is shown first at normal speed and then in slow-motion as he clears a bar at 11.5 feet. Measure the total energy of the system at two times just before the jumper starts to rise, and part way up when the pole has a distorted shape. The total energy of the system is constant, although it is divided up differently at different times. Since it takes work to bend the pole, the pole has elastic potential energy when bent. This plastic energy comes from some of the kinetic energy the vaulter has as he runs horizontally before inserting the pole into the socket. Later, the elastic potential energy of the bent pole is transformed into some of the jumper's gravitational potential energy when he is at the top of the jump. POSITION 1:The energy is entirely kinetic energy, 1/2 mv squared. To aid in measuring the runner's speed, successive frames are held as the runner moves past two markers 1 meter apart. Each "freeze frame" represents a time interval of 1/250 sec since the film runs through at this number of frames per second. Find the runner's average speed over this meter, and then find the kinetic energy. If m is in kg and v is in m/sec, E will be in joules. POSITION 2: The jumper's center of gravity is about 1.02 meters above the soles of his feet. Three types of energy are involved at the intermediate position. Use the stop-frame sequence to obtain the speed of the jumper. (The seat of his pants can be used as a reference. ) Calculate the kinetic energy and gravitational potential energy as already described. The work done in deforming the pole is stored as elastic potential energy. In the final scene, a chain windlass bends the pole to a shape similar to that which it assumes during the jump in position 2. When the chain is shortened, work is done on the pole: work = (average force ) X (displacement) . During the cranking sequence the force varied. The average force can be approximated by adding the initial and final values, found from the scale, and then dividing by two. Convert this force to newtons. The displacement can be estimated from the number of times the crank handle is pulled. A close-up shows how far the chain moves during a single stroke. Calculate the work done to crank the pole into its distorted shape. You can now add and find the total energy. How does this compare with the original kinetic energy?